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For files with regions of numbers and other characters, it's intuitive to have the numbers sorted by increasing numeric value rather than by ASCII code. (Jeff Atwood has a nice article here: https://blog.codinghorror.com/sorting-for-humans-natural-sort-order/) For example, the listing for a directory containing `foo1`, `foo2`, and `foo10` would sort in that order, rather than putting `foo10` between `foo1` and `foo2`. Closes #7226
65 lines
2.1 KiB
Go
65 lines
2.1 KiB
Go
package fileserver
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func isDigit(b byte) bool { return '0' <= b && b <= '9' }
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// naturalLess compares two strings using natural ordering. This means that e.g.
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// "abc2" < "abc12".
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//
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// Non-digit sequences and numbers are compared separately. The former are
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// compared bytewise, while digits are compared numerically (except that
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// the number of leading zeros is used as a tie-breaker, so e.g. "2" < "02")
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//
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// Limitation: only ASCII digits (0-9) are considered.
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//
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// This implementation is copied from https://github.com/fvbommel/sortorder,
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// which is MIT licensed.
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func naturalLess(str1, str2 string) bool {
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idx1, idx2 := 0, 0
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for idx1 < len(str1) && idx2 < len(str2) {
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c1, c2 := str1[idx1], str2[idx2]
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dig1, dig2 := isDigit(c1), isDigit(c2)
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switch {
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case dig1 != dig2: // Digits before other characters.
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return dig1 // True if LHS is a digit, false if the RHS is one.
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case !dig1: // && !dig2, because dig1 == dig2
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// UTF-8 compares bytewise-lexicographically, no need to decode
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// codepoints.
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if c1 != c2 {
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return c1 < c2
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}
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idx1++
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idx2++
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default: // Digits
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// Eat zeros.
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for ; idx1 < len(str1) && str1[idx1] == '0'; idx1++ {
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}
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for ; idx2 < len(str2) && str2[idx2] == '0'; idx2++ {
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}
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// Eat all digits.
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nonZero1, nonZero2 := idx1, idx2
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for ; idx1 < len(str1) && isDigit(str1[idx1]); idx1++ {
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}
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for ; idx2 < len(str2) && isDigit(str2[idx2]); idx2++ {
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}
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// If lengths of numbers with non-zero prefix differ, the shorter
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// one is less.
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if len1, len2 := idx1-nonZero1, idx2-nonZero2; len1 != len2 {
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return len1 < len2
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}
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// If they're equally long, string comparison is correct.
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if nr1, nr2 := str1[nonZero1:idx1], str2[nonZero2:idx2]; nr1 != nr2 {
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return nr1 < nr2
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}
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// Otherwise, the one with less zeros is less.
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// Because everything up to the number is equal, comparing the index
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// after the zeros is sufficient.
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if nonZero1 != nonZero2 {
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return nonZero1 < nonZero2
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}
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}
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// They're identical so far, so continue comparing.
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}
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// So far they are identical. At least one is ended. If the other continues,
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// it sorts last.
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return len(str1) < len(str2)
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}
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