cpython/Doc/faq/design.rst

======================
Design and History FAQ
======================

.. only:: html

   .. contents::


Why does Python use indentation for grouping of statements?
-----------------------------------------------------------

Guido van Rossum believes that using indentation for grouping is extremely
elegant and contributes a lot to the clarity of the average Python program.
Most people learn to love this feature after a while.

Since there are no begin/end brackets there cannot be a disagreement between
grouping perceived by the parser and the human reader.  Occasionally C
programmers will encounter a fragment of code like this::

   if (x <= y)
           x++;
           y--;
   z++;

Only the ``x++`` statement is executed if the condition is true, but the
indentation leads many to believe otherwise.  Even experienced C programmers will
sometimes stare at it a long time wondering as to why ``y`` is being decremented even
for ``x > y``.

Because there are no begin/end brackets, Python is much less prone to
coding-style conflicts.  In C there are many different ways to place the braces.
After becoming used to reading and writing code using a particular style,
it is normal to feel somewhat uneasy when reading (or being required to write)
in a different one.


Many coding styles place begin/end brackets on a line by themselves.  This makes
programs considerably longer and wastes valuable screen space, making it harder
to get a good overview of a program.  Ideally, a function should fit on one
screen (say, 20--30 lines).  20 lines of Python can do a lot more work than 20
lines of C.  This is not solely due to the lack of begin/end brackets -- the
lack of declarations and the high-level data types are also responsible -- but
the indentation-based syntax certainly helps.


Why am I getting strange results with simple arithmetic operations?
-------------------------------------------------------------------

See the next question.


Why are floating-point calculations so inaccurate?
--------------------------------------------------

Users are often surprised by results like this::

    >>> 1.2 - 1.0
    0.19999999999999996

and think it is a bug in Python.  It's not.  This has little to do with Python,
and much more to do with how the underlying platform handles floating-point
numbers.

The :class:`float` type in CPython uses a C ``double`` for storage.  A
:class:`float` object's value is stored in binary floating-point with a fixed
precision (typically 53 bits) and Python uses C operations, which in turn rely
on the hardware implementation in the processor, to perform floating-point
operations. This means that as far as floating-point operations are concerned,
Python behaves like many popular languages including C and Java.

Many numbers that can be written easily in decimal notation cannot be expressed
exactly in binary floating-point.  For example, after::

    >>> x = 1.2

the value stored for ``x`` is a (very good) approximation to the decimal value
``1.2``, but is not exactly equal to it.  On a typical machine, the actual
stored value is::

    1.0011001100110011001100110011001100110011001100110011 (binary)

which is exactly::

    1.1999999999999999555910790149937383830547332763671875 (decimal)

The typical precision of 53 bits provides Python floats with 15--16
decimal digits of accuracy.

For a fuller explanation, please see the :ref:`floating point arithmetic
<tut-fp-issues>` chapter in the Python tutorial.


Why are Python strings immutable?
---------------------------------

There are several advantages.

One is performance: knowing that a string is immutable means we can allocate
space for it at creation time, and the storage requirements are fixed and
unchanging.  This is also one of the reasons for the distinction between tuples
and lists.

Another advantage is that strings in Python are considered as "elemental" as
numbers.  No amount of activity will change the value 8 to anything else, and in
Python, no amount of activity will change the string "eight" to anything else.


.. _why-self:

Why must 'self' be used explicitly in method definitions and calls?
-------------------------------------------------------------------

The idea was borrowed from Modula-3.  It turns out to be very useful, for a
variety of reasons.

First, it's more obvious that you are using a method or instance attribute
instead of a local variable.  Reading ``self.x`` or ``self.meth()`` makes it
absolutely clear that an instance variable or method is used even if you don't
know the class definition by heart.  In C++, you can sort of tell by the lack of
a local variable declaration (assuming globals are rare or easily recognizable)
-- but in Python, there are no local variable declarations, so you'd have to
look up the class definition to be sure.  Some C++ and Java coding standards
call for instance attributes to have an ``m_`` prefix, so this explicitness is
still useful in those languages, too.

Second, it means that no special syntax is necessary if you want to explicitly
reference or call the method from a particular class.  In C++, if you want to
use a method from a base class which is overridden in a derived class, you have
to use the ``::`` operator -- in Python you can write
``baseclass.methodname(self, <argument list>)``.  This is particularly useful
for :meth:`~object.__init__` methods, and in general in cases where a derived class
method wants to extend the base class method of the same name and thus has to
call the base class method somehow.

Finally, for instance variables it solves a syntactic problem with assignment:
since local variables in Python are (by definition!) those variables to which a
value is assigned in a function body (and that aren't explicitly declared
global), there has to be some way to tell the interpreter that an assignment was
meant to assign to an instance variable instead of to a local variable, and it
should preferably be syntactic (for efficiency reasons).  C++ does this through
declarations, but Python doesn't have declarations and it would be a pity having
to introduce them just for this purpose.  Using the explicit ``self.var`` solves
this nicely.  Similarly, for using instance variables, having to write
``self.var`` means that references to unqualified names inside a method don't
have to search the instance's directories.  To put it another way, local
variables and instance variables live in two different namespaces, and you need
to tell Python which namespace to use.


.. _why-can-t-i-use-an-assignment-in-an-expression:

Why can't I use an assignment in an expression?
-----------------------------------------------

Starting in Python 3.8, you can!

Assignment expressions using the walrus operator ``:=`` assign a variable in an
expression::

   while chunk := fp.read(200):
      print(chunk)

See :pep:`572` for more information.



Why does Python use methods for some functionality (e.g. list.index()) but functions for other (e.g. len(list))?
----------------------------------------------------------------------------------------------------------------

As Guido said:

    (a) For some operations, prefix notation just reads better than
    postfix -- prefix (and infix!) operations have a long tradition in
    mathematics which likes notations where the visuals help the
    mathematician thinking about a problem. Compare the easy with which we
    rewrite a formula like x*(a+b) into x*a + x*b to the clumsiness of
    doing the same thing using a raw OO notation.

    (b) When I read code that says len(x) I *know* that it is asking for
    the length of something. This tells me two things: the result is an
    integer, and the argument is some kind of container. To the contrary,
    when I read x.len(), I have to already know that x is some kind of
    container implementing an interface or inheriting from a class that
    has a standard len(). Witness the confusion we occasionally have when
    a class that is not implementing a mapping has a get() or keys()
    method, or something that isn't a file has a write() method.

    -- https://mail.python.org/pipermail/python-3000/2006-November/004643.html


Why is join() a string method instead of a list or tuple method?
----------------------------------------------------------------

Strings became much more like other standard types starting in Python 1.6, when
methods were added which give the same functionality that has always been
available using the functions of the string module.  Most of these new methods
have been widely accepted, but the one which appears to make some programmers
feel uncomfortable is::

   ", ".join(['1', '2', '4', '8', '16'])

which gives the result::

   "1, 2, 4, 8, 16"

There are two common arguments against this usage.

The first runs along the lines of: "It looks really ugly using a method of a
string literal (string constant)", to which the answer is that it might, but a
string literal is just a fixed value. If the methods are to be allowed on names
bound to strings there is no logical reason to make them unavailable on
literals.

The second objection is typically cast as: "I am really telling a sequence to
join its members together with a string constant".  Sadly, you aren't.  For some
reason there seems to be much less difficulty with having :meth:`~str.split` as
a string method, since in that case it is easy to see that ::

   "1, 2, 4, 8, 16".split(", ")

is an instruction to a string literal to return the substrings delimited by the
given separator (or, by default, arbitrary runs of white space).

:meth:`~str.join` is a string method because in using it you are telling the
separator string to iterate over a sequence of strings and insert itself between
adjacent elements.  This method can be used with any argument which obeys the
rules for sequence objects, including any new classes you might define yourself.
Similar methods exist for bytes and bytearray objects.


How fast are exceptions?
------------------------

A :keyword:`try`/:keyword:`except` block is extremely efficient if no exceptions
are raised.  Actually
catching an exception is expensive.  In versions of Python prior to 2.0 it was
common to use this idiom::

   try:
       value = mydict[key]
   except KeyError:
       mydict[key] = getvalue(key)
       value = mydict[key]

This only made sense when you expected the dict to have the key almost all the
time.  If that wasn't the case, you coded it like this::

   if key in mydict:
       value = mydict[key]
   else:
       value = mydict[key] = getvalue(key)

For this specific case, you could also use ``value = dict.setdefault(key,
getvalue(key))``, but only if the ``getvalue()`` call is cheap enough because it
is evaluated in all cases.


Why isn't there a switch or case statement in Python?
-----------------------------------------------------

You can do this easily enough with a sequence of ``if... elif... elif... else``.
For literal values, or constants within a namespace, you can also use a
``match ... case`` statement.

For cases where you need to choose from a very large number of possibilities,
you can create a dictionary mapping case values to functions to call.  For
example::

   functions = {'a': function_1,
                'b': function_2,
                'c': self.method_1}

   func = functions[value]
   func()

For calling methods on objects, you can simplify yet further by using the
:func:`getattr` built-in to retrieve methods with a particular name::

   class MyVisitor:
       def visit_a(self):
           ...

       def dispatch(self, value):
           method_name = 'visit_' + str(value)
           method = getattr(self, method_name)
           method()

It's suggested that you use a prefix for the method names, such as ``visit_`` in
this example.  Without such a prefix, if values are coming from an untrusted
source, an attacker would be able to call any method on your object.


Can't you emulate threads in the interpreter instead of relying on an OS-specific thread implementation?
--------------------------------------------------------------------------------------------------------

Answer 1: Unfortunately, the interpreter pushes at least one C stack frame for
each Python stack frame.  Also, extensions can call back into Python at almost
random moments.  Therefore, a complete threads implementation requires thread
support for C.

Answer 2: Fortunately, there is `Stackless Python <https://github.com/stackless-dev/stackless/wiki>`_,
which has a completely redesigned interpreter loop that avoids the C stack.


Why can't lambda expressions contain statements?
------------------------------------------------

Python lambda expressions cannot contain statements because Python's syntactic
framework can't handle statements nested inside expressions.  However, in
Python, this is not a serious problem.  Unlike lambda forms in other languages,
where they add functionality, Python lambdas are only a shorthand notation if
you're too lazy to define a function.

Functions are already first class objects in Python, and can be declared in a
local scope.  Therefore the only advantage of using a lambda instead of a
locally defined function is that you don't need to invent a name for the
function -- but that's just a local variable to which the function object (which
is exactly the same type of object that a lambda expression yields) is assigned!


Can Python be compiled to machine code, C or some other language?
-----------------------------------------------------------------

`Cython <https://cython.org/>`_ compiles a modified version of Python with
optional annotations into C extensions.  `Nuitka <https://www.nuitka.net/>`_ is
an up-and-coming compiler of Python into C++ code, aiming to support the full
Python language.


How does Python manage memory?
------------------------------

The details of Python memory management depend on the implementation.  The
standard implementation of Python, :term:`CPython`, uses reference counting to
detect inaccessible objects, and another mechanism to collect reference cycles,
periodically executing a cycle detection algorithm which looks for inaccessible
cycles and deletes the objects involved. The :mod:`gc` module provides functions
to perform a garbage collection, obtain debugging statistics, and tune the
collector's parameters.

Other implementations (such as `Jython <https://www.jython.org>`_ or
`PyPy <https://www.pypy.org>`_), however, can rely on a different mechanism
such as a full-blown garbage collector.  This difference can cause some
subtle porting problems if your Python code depends on the behavior of the
reference counting implementation.

In some Python implementations, the following code (which is fine in CPython)
will probably run out of file descriptors::

   for file in very_long_list_of_files:
       f = open(file)
       c = f.read(1)

Indeed, using CPython's reference counting and destructor scheme, each new
assignment to ``f`` closes the previous file.  With a traditional GC, however,
those file objects will only get collected (and closed) at varying and possibly
long intervals.

If you want to write code that will work with any Python implementation,
you should explicitly close the file or use the :keyword:`with` statement;
this will work regardless of memory management scheme::

   for file in very_long_list_of_files:
       with open(file) as f:
           c = f.read(1)


Why doesn't CPython use a more traditional garbage collection scheme?
---------------------------------------------------------------------

For one thing, this is not a C standard feature and hence it's not portable.
(Yes, we know about the Boehm GC library.  It has bits of assembler code for
*most* common platforms, not for all of them, and although it is mostly
transparent, it isn't completely transparent; patches are required to get
Python to work with it.)

Traditional GC also becomes a problem when Python is embedded into other
applications.  While in a standalone Python it's fine to replace the standard
``malloc()`` and ``free()`` with versions provided by the GC library, an application
embedding Python may want to have its *own* substitute for ``malloc()`` and ``free()``,
and may not want Python's.  Right now, CPython works with anything that
implements ``malloc()`` and ``free()`` properly.


Why isn't all memory freed when CPython exits?
----------------------------------------------

Objects referenced from the global namespaces of Python modules are not always
deallocated when Python exits.  This may happen if there are circular
references.  There are also certain bits of memory that are allocated by the C
library that are impossible to free (e.g. a tool like Purify will complain about
these).  Python is, however, aggressive about cleaning up memory on exit and
does try to destroy every single object.

If you want to force Python to delete certain things on deallocation use the
:mod:`atexit` module to run a function that will force those deletions.


Why are there separate tuple and list data types?
-------------------------------------------------

Lists and tuples, while similar in many respects, are generally used in
fundamentally different ways.  Tuples can be thought of as being similar to
Pascal ``records`` or C ``structs``; they're small collections of related data which may
be of different types which are operated on as a group.  For example, a
Cartesian coordinate is appropriately represented as a tuple of two or three
numbers.

Lists, on the other hand, are more like arrays in other languages.  They tend to
hold a varying number of objects all of which have the same type and which are
operated on one-by-one.  For example, :func:`os.listdir('.') <os.listdir>`
returns a list of
strings representing the files in the current directory.  Functions which
operate on this output would generally not break if you added another file or
two to the directory.

Tuples are immutable, meaning that once a tuple has been created, you can't
replace any of its elements with a new value.  Lists are mutable, meaning that
you can always change a list's elements.  Only immutable elements can be used as
dictionary keys, and hence only tuples and not lists can be used as keys.


How are lists implemented in CPython?
-------------------------------------

CPython's lists are really variable-length arrays, not Lisp-style linked lists.
The implementation uses a contiguous array of references to other objects, and
keeps a pointer to this array and the array's length in a list head structure.

This makes indexing a list ``a[i]`` an operation whose cost is independent of
the size of the list or the value of the index.

When items are appended or inserted, the array of references is resized.  Some
cleverness is applied to improve the performance of appending items repeatedly;
when the array must be grown, some extra space is allocated so the next few
times don't require an actual resize.


How are dictionaries implemented in CPython?
--------------------------------------------

CPython's dictionaries are implemented as resizable hash tables.  Compared to
B-trees, this gives better performance for lookup (the most common operation by
far) under most circumstances, and the implementation is simpler.

Dictionaries work by computing a hash code for each key stored in the dictionary
using the :func:`hash` built-in function.  The hash code varies widely depending
on the key and a per-process seed; for example, ``'Python'`` could hash to
``-539294296`` while ``'python'``, a string that differs by a single bit, could hash
to ``1142331976``.  The hash code is then used to calculate a location in an
internal array where the value will be stored.  Assuming that you're storing
keys that all have different hash values, this means that dictionaries take
constant time -- *O*\ (1), in Big-O notation -- to retrieve a key.


Why must dictionary keys be immutable?
--------------------------------------

The hash table implementation of dictionaries uses a hash value calculated from
the key value to find the key.  If the key were a mutable object, its value
could change, and thus its hash could also change.  But since whoever changes
the key object can't tell that it was being used as a dictionary key, it can't
move the entry around in the dictionary.  Then, when you try to look up the same
object in the dictionary it won't be found because its hash value is different.
If you tried to look up the old value it wouldn't be found either, because the
value of the object found in that hash bin would be different.

If you want a dictionary indexed with a list, simply convert the list to a tuple
first; the function ``tuple(L)`` creates a tuple with the same entries as the
list ``L``.  Tuples are immutable and can therefore be used as dictionary keys.

Some unacceptable solutions that have been proposed:

- Hash lists by their address (object ID).  This doesn't work because if you
  construct a new list with the same value it won't be found; e.g.::

     mydict = {[1, 2]: '12'}
     print(mydict[[1, 2]])

  would raise a :exc:`KeyError` exception because the id of the ``[1, 2]`` used in the
  second line differs from that in the first line.  In other words, dictionary
  keys should be compared using ``==``, not using :keyword:`is`.

- Make a copy when using a list as a key.  This doesn't work because the list,
  being a mutable object, could contain a reference to itself, and then the
  copying code would run into an infinite loop.

- Allow lists as keys but tell the user not to modify them.  This would allow a
  class of hard-to-track bugs in programs when you forgot or modified a list by
  accident. It also invalidates an important invariant of dictionaries: every
  value in ``d.keys()`` is usable as a key of the dictionary.

- Mark lists as read-only once they are used as a dictionary key.  The problem
  is that it's not just the top-level object that could change its value; you
  could use a tuple containing a list as a key.  Entering anything as a key into
  a dictionary would require marking all objects reachable from there as
  read-only -- and again, self-referential objects could cause an infinite loop.

There is a trick to get around this if you need to, but use it at your own risk:
You can wrap a mutable structure inside a class instance which has both a
:meth:`~object.__eq__` and a :meth:`~object.__hash__` method.
You must then make sure that the
hash value for all such wrapper objects that reside in a dictionary (or other
hash based structure), remain fixed while the object is in the dictionary (or
other structure). ::

   class ListWrapper:
       def __init__(self, the_list):
           self.the_list = the_list

       def __eq__(self, other):
           return self.the_list == other.the_list

       def __hash__(self):
           l = self.the_list
           result = 98767 - len(l)*555
           for i, el in enumerate(l):
               try:
                   result = result + (hash(el) % 9999999) * 1001 + i
               except Exception:
                   result = (result % 7777777) + i * 333
           return result

Note that the hash computation is complicated by the possibility that some
members of the list may be unhashable and also by the possibility of arithmetic
overflow.

Furthermore it must always be the case that if ``o1 == o2`` (ie ``o1.__eq__(o2)
is True``) then ``hash(o1) == hash(o2)`` (ie, ``o1.__hash__() == o2.__hash__()``),
regardless of whether the object is in a dictionary or not.  If you fail to meet
these restrictions dictionaries and other hash based structures will misbehave.

In the case of :class:`!ListWrapper`, whenever the wrapper object is in a dictionary the
wrapped list must not change to avoid anomalies.  Don't do this unless you are
prepared to think hard about the requirements and the consequences of not
meeting them correctly.  Consider yourself warned.


Why doesn't list.sort() return the sorted list?
-----------------------------------------------

In situations where performance matters, making a copy of the list just to sort
it would be wasteful. Therefore, :meth:`list.sort` sorts the list in place. In
order to remind you of that fact, it does not return the sorted list.  This way,
you won't be fooled into accidentally overwriting a list when you need a sorted
copy but also need to keep the unsorted version around.

If you want to return a new list, use the built-in :func:`sorted` function
instead.  This function creates a new list from a provided iterable, sorts
it and returns it.  For example, here's how to iterate over the keys of a
dictionary in sorted order::

   for key in sorted(mydict):
       ...  # do whatever with mydict[key]...


How do you specify and enforce an interface spec in Python?
-----------------------------------------------------------

An interface specification for a module as provided by languages such as C++ and
Java describes the prototypes for the methods and functions of the module.  Many
feel that compile-time enforcement of interface specifications helps in the
construction of large programs.

Python 2.6 adds an :mod:`abc` module that lets you define Abstract Base Classes
(ABCs).  You can then use :func:`isinstance` and :func:`issubclass` to check
whether an instance or a class implements a particular ABC.  The
:mod:`collections.abc` module defines a set of useful ABCs such as
:class:`~collections.abc.Iterable`, :class:`~collections.abc.Container`, and
:class:`~collections.abc.MutableMapping`.

For Python, many of the advantages of interface specifications can be obtained
by an appropriate test discipline for components.

A good test suite for a module can both provide a regression test and serve as a
module interface specification and a set of examples.  Many Python modules can
be run as a script to provide a simple "self test."  Even modules which use
complex external interfaces can often be tested in isolation using trivial
"stub" emulations of the external interface.  The :mod:`doctest` and
:mod:`unittest` modules or third-party test frameworks can be used to construct
exhaustive test suites that exercise every line of code in a module.

An appropriate testing discipline can help build large complex applications in
Python as well as having interface specifications would.  In fact, it can be
better because an interface specification cannot test certain properties of a
program.  For example, the :meth:`!list.append` method is expected to add new elements
to the end of some internal list; an interface specification cannot test that
your :meth:`!list.append` implementation will actually do this correctly, but it's
trivial to check this property in a test suite.

Writing test suites is very helpful, and you might want to design your code to
make it easily tested. One increasingly popular technique, test-driven
development, calls for writing parts of the test suite first, before you write
any of the actual code.  Of course Python allows you to be sloppy and not write
test cases at all.


Why is there no goto?
---------------------

In the 1970s people realized that unrestricted goto could lead
to messy "spaghetti" code that was hard to understand and revise.
In a high-level language, it is also unneeded as long as there
are ways to branch (in Python, with :keyword:`if` statements and :keyword:`or`,
:keyword:`and`, and :keyword:`if`/:keyword:`else` expressions) and loop (with :keyword:`while`
and :keyword:`for` statements, possibly containing :keyword:`continue` and :keyword:`break`).

One can also use exceptions to provide a "structured goto"
that works even across
function calls.  Many feel that exceptions can conveniently emulate all
reasonable uses of the ``go`` or ``goto`` constructs of C, Fortran, and other
languages.  For example::

   class label(Exception): pass  # declare a label

   try:
       ...
       if condition: raise label()  # goto label
       ...
   except label:  # where to goto
       pass
   ...

This doesn't allow you to jump into the middle of a loop, but that's usually
considered an abuse of ``goto`` anyway.  Use sparingly.


Why can't raw strings (r-strings) end with a backslash?
-------------------------------------------------------

More precisely, they can't end with an odd number of backslashes: the unpaired
backslash at the end escapes the closing quote character, leaving an
unterminated string.

Raw strings were designed to ease creating input for processors (chiefly regular
expression engines) that want to do their own backslash escape processing. Such
processors consider an unmatched trailing backslash to be an error anyway, so
raw strings disallow that.  In return, they allow you to pass on the string
quote character by escaping it with a backslash.  These rules work well when
r-strings are used for their intended purpose.

If you're trying to build Windows pathnames, note that all Windows system calls
accept forward slashes too::

   f = open("/mydir/file.txt")  # works fine!

If you're trying to build a pathname for a DOS command, try e.g. one of ::

   dir = r"\this\is\my\dos\dir" "\\"
   dir = r"\this\is\my\dos\dir\ "[:-1]
   dir = "\\this\\is\\my\\dos\\dir\\"


Why doesn't Python have a "with" statement for attribute assignments?
---------------------------------------------------------------------

Python has a :keyword:`with` statement that wraps the execution of a block, calling code
on the entrance and exit from the block.  Some languages have a construct that
looks like this::

   with obj:
       a = 1               # equivalent to obj.a = 1
       total = total + 1   # obj.total = obj.total + 1

In Python, such a construct would be ambiguous.

Other languages, such as Object Pascal, Delphi, and C++, use static types, so
it's possible to know, in an unambiguous way, what member is being assigned
to. This is the main point of static typing -- the compiler *always* knows the
scope of every variable at compile time.

Python uses dynamic types. It is impossible to know in advance which attribute
will be referenced at runtime. Member attributes may be added or removed from
objects on the fly. This makes it impossible to know, from a simple reading,
what attribute is being referenced: a local one, a global one, or a member
attribute?

For instance, take the following incomplete snippet::

   def foo(a):
       with a:
           print(x)

The snippet assumes that ``a`` must have a member attribute called ``x``. However,
there is nothing in Python that tells the interpreter this. What should happen
if ``a`` is, let us say, an integer?  If there is a global variable named ``x``,
will it be used inside the :keyword:`with` block?  As you see, the dynamic nature of Python
makes such choices much harder.

The primary benefit of :keyword:`with` and similar language features (reduction of code
volume) can, however, easily be achieved in Python by assignment.  Instead of::

   function(args).mydict[index][index].a = 21
   function(args).mydict[index][index].b = 42
   function(args).mydict[index][index].c = 63

write this::

   ref = function(args).mydict[index][index]
   ref.a = 21
   ref.b = 42
   ref.c = 63

This also has the side-effect of increasing execution speed because name
bindings are resolved at run-time in Python, and the second version only needs
to perform the resolution once.

Similar proposals that would introduce syntax to further reduce code volume,
such as using a 'leading dot', have been rejected in favour of explicitness (see
https://mail.python.org/pipermail/python-ideas/2016-May/040070.html).


Why don't generators support the with statement?
------------------------------------------------

For technical reasons, a generator used directly as a context manager
would not work correctly.  When, as is most common, a generator is used as
an iterator run to completion, no closing is needed.  When it is, wrap
it as :func:`contextlib.closing(generator) <contextlib.closing>`
in the :keyword:`with` statement.


Why are colons required for the if/while/def/class statements?
--------------------------------------------------------------

The colon is required primarily to enhance readability (one of the results of
the experimental ABC language).  Consider this::

   if a == b
       print(a)

versus ::

   if a == b:
       print(a)

Notice how the second one is slightly easier to read.  Notice further how a
colon sets off the example in this FAQ answer; it's a standard usage in English.

Another minor reason is that the colon makes it easier for editors with syntax
highlighting; they can look for colons to decide when indentation needs to be
increased instead of having to do a more elaborate parsing of the program text.


Why does Python allow commas at the end of lists and tuples?
------------------------------------------------------------

Python lets you add a trailing comma at the end of lists, tuples, and
dictionaries::

   [1, 2, 3,]
   ('a', 'b', 'c',)
   d = {
       "A": [1, 5],
       "B": [6, 7],  # last trailing comma is optional but good style
   }


There are several reasons to allow this.

When you have a literal value for a list, tuple, or dictionary spread across
multiple lines, it's easier to add more elements because you don't have to
remember to add a comma to the previous line.  The lines can also be reordered
without creating a syntax error.

Accidentally omitting the comma can lead to errors that are hard to diagnose.
For example::

       x = [
         "fee",
         "fie"
         "foo",
         "fum"
       ]

This list looks like it has four elements, but it actually contains three:
"fee", "fiefoo" and "fum".  Always adding the comma avoids this source of error.

Allowing the trailing comma may also make programmatic code generation easier.