2021-09-20 11:36:57 +03:00
										 
									 
								 
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								import doctest
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								import unittest
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											2007-04-15 12:05:43 +00:00
										 
									 
								 
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								doctests = """
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								########### Tests mostly copied from test_listcomps.py ############
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								Test simple loop with conditional
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								    >>> sum({i*i for i in range(100) if i&1 == 1})
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								    166650
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								Test simple case
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								    >>> {2*y + x + 1 for x in (0,) for y in (1,)}
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								    {3}
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								Test simple nesting
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								    >>> list(sorted({(i,j) for i in range(3) for j in range(4)}))
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								    [(0, 0), (0, 1), (0, 2), (0, 3), (1, 0), (1, 1), (1, 2), (1, 3), (2, 0), (2, 1), (2, 2), (2, 3)]
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								Test nesting with the inner expression dependent on the outer
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								    >>> list(sorted({(i,j) for i in range(4) for j in range(i)}))
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								    [(1, 0), (2, 0), (2, 1), (3, 0), (3, 1), (3, 2)]
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											2020-02-12 12:18:59 +02:00
										 
									 
								 
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								Test the idiom for temporary variable assignment in comprehensions.
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								    >>> sorted({j*j for i in range(4) for j in [i+1]})
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								    [1, 4, 9, 16]
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								    >>> sorted({j*k for i in range(4) for j in [i+1] for k in [j+1]})
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								    [2, 6, 12, 20]
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								    >>> sorted({j*k for i in range(4) for j, k in [(i+1, i+2)]})
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								    [2, 6, 12, 20]
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								Not assignment
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								    >>> sorted({i*i for i in [*range(4)]})
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								    [0, 1, 4, 9]
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								    >>> sorted({i*i for i in (*range(4),)})
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								    [0, 1, 4, 9]
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											2007-04-15 12:05:43 +00:00
										 
									 
								 
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								Make sure the induction variable is not exposed
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								    >>> i = 20
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								    >>> sum({i*i for i in range(100)})
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								    328350
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								    >>> i
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								    20
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								Verify that syntax error's are raised for setcomps used as lvalues
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								    >>> {y for y in (1,2)} = 10          # doctest: +IGNORE_EXCEPTION_DETAIL
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								    Traceback (most recent call last):
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								       ...
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								    SyntaxError: ...
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								    >>> {y for y in (1,2)} += 10         # doctest: +IGNORE_EXCEPTION_DETAIL
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								    Traceback (most recent call last):
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								       ...
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								    SyntaxError: ...
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											2007-05-07 22:24:25 +00:00
										 
									 
								 
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								Make a nested set comprehension that acts like set(range())
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											2007-04-15 12:05:43 +00:00
										 
									 
								 
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								    >>> def srange(n):
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											2007-05-07 22:24:25 +00:00
										 
									 
								 
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								    ...     return {i for i in range(n)}
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											2007-04-15 12:05:43 +00:00
										 
									 
								 
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								    >>> list(sorted(srange(10)))
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								    [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
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								Same again, only as a lambda expression instead of a function definition
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											2007-05-07 22:24:25 +00:00
										 
									 
								 
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								    >>> lrange = lambda n:  {i for i in range(n)}
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								    >>> list(sorted(lrange(10)))
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								    [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
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								Generators can call other generators:
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								    >>> def grange(n):
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								    ...     for x in {i for i in range(n)}:
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								    ...         yield x
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								    >>> list(sorted(grange(5)))
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								    [0, 1, 2, 3, 4]
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								Make sure that None is a valid return value
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											2007-05-07 22:24:25 +00:00
										 
									 
								 
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								    >>> {None for i in range(10)}
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											2007-04-15 12:05:43 +00:00
										 
									 
								 
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								    {None}
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								########### Tests for various scoping corner cases ############
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								Return lambdas that use the iteration variable as a default argument
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								    >>> items = {(lambda i=i: i) for i in range(5)}
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								    >>> {x() for x in items} == set(range(5))
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								    True
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								Same again, only this time as a closure variable
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								    >>> items = {(lambda: i) for i in range(5)}
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								    >>> {x() for x in items}
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								    {4}
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								Another way to test that the iteration variable is local to the list comp
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								    >>> items = {(lambda: i) for i in range(5)}
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								    >>> i = 20
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								    >>> {x() for x in items}
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								    {4}
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								And confirm that a closure can jump over the list comp scope
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								    >>> items = {(lambda: y) for i in range(5)}
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								    >>> y = 2
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								    >>> {x() for x in items}
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								    {2}
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								We also repeat each of the above scoping tests inside a function
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								    >>> def test_func():
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								    ...     items = {(lambda i=i: i) for i in range(5)}
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								    ...     return {x() for x in items}
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								    >>> test_func() == set(range(5))
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								    True
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								    >>> def test_func():
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								    ...     items = {(lambda: i) for i in range(5)}
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								    ...     return {x() for x in items}
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								    >>> test_func()
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								    {4}
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								    >>> def test_func():
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								    ...     items = {(lambda: i) for i in range(5)}
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								    ...     i = 20
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								    ...     return {x() for x in items}
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								    >>> test_func()
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								    {4}
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								    >>> def test_func():
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								    ...     items = {(lambda: y) for i in range(5)}
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								    ...     y = 2
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								    ...     return {x() for x in items}
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								    >>> test_func()
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								    {2}
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								"""
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								__test__ = {'doctests' : doctests}
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											2021-09-20 11:36:57 +03:00
										 
									 
								 
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								def load_tests(loader, tests, pattern):
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								    tests.addTest(doctest.DocTestSuite())
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								    return tests
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											2007-04-15 12:05:43 +00:00
										 
									 
								 
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								if __name__ == "__main__":
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								    unittest.main()
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