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Fix an unfortunate mis-conversion: sometimes "print x," must be

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converted to "print(x, end=' ')", but other times it must be converted
to "print(x, end='')".  There's no easy way to find out, because it
depends on whether x ends with a newline.  I'm sure I'll find more
like this.
This commit is contained in:
Guido van Rossum 2007-02-09 20:50:08 +00:00
parent fff80dfa4a
commit 08c47ba0df
1 changed files with 3 additions and 3 deletions
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6
Lib/test/regrtest.py
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@ -738,19 +738,19 @@ def pair(x0, x1):
elif op == 'delete': elif op == 'delete':
print("***", pair(a0, a1), "of expected output missing:") print("***", pair(a0, a1), "of expected output missing:")
for line in a[a0:a1]: for line in a[a0:a1]:
print("-", line, end=' ') print("-", line, end='')
elif op == 'replace': elif op == 'replace':
print("*** mismatch between", pair(a0, a1), "of expected", \ print("*** mismatch between", pair(a0, a1), "of expected", \
"output and", pair(b0, b1), "of actual output:") "output and", pair(b0, b1), "of actual output:")
for line in difflib.ndiff(a[a0:a1], b[b0:b1]): for line in difflib.ndiff(a[a0:a1], b[b0:b1]):
print(line, end=' ') print(line, end='')
elif op == 'insert': elif op == 'insert':
print("***", pair(b0, b1), "of actual output doesn't appear", \ print("***", pair(b0, b1), "of actual output doesn't appear", \
"in expected output after line", str(a1)+":") "in expected output after line", str(a1)+":")
for line in b[b0:b1]: for line in b[b0:b1]:
print("+", line, end=' ') print("+", line, end='')
else: else:
print("get_opcodes() returned bad tuple?!?!", (op, a0, a1, b0, b1)) print("get_opcodes() returned bad tuple?!?!", (op, a0, a1, b0, b1))