Stowage/cpython
2
0
Fork 0
mirror of https://github.com/python/cpython.git synced 2026-01-06 15:32:22 +00:00
Code Issues Projects Releases Packages Wiki Activity

Fixing wording in comment. (GH-10425)

Browse source 
Since the n==1 case just returns *max*, it cannot be larger
than the magnitude of the vector entry.
This commit is contained in:
Raymond Hettinger 2018-11-09 01:06:02 -08:00 • committed by Miss Islington (bot)
parent 7a69cf47a9
commit 216aaaa056
1 changed files with 1 additions and 1 deletions
Download patch file Download diff file Expand all files Collapse all files

2
Modules/mathmodule.c
View file

@ -2043,7 +2043,7 @@ Given an *n* length *vec* of values and a value *max*, compute:
max * sqrt(sum((x / max) ** 2 for x in vec))
The value of the *max* variable must be non-negative and
at least equal to the absolute value of the largest magnitude
equal to the absolute value of the largest magnitude
entry in the vector. If n==0, then *max* should be 0.0.
If an infinity is present in the vec, *max* should be INF.