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Issue #21566: Make use of socket.listen() default backlog.

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This commit is contained in:
Charles-François Natali 2014-07-23 19:28:13 +01:00
parent 8518b79a8d
commit 6e20460dc6
18 changed files with 33 additions and 33 deletions
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10
Lib/test/test_ssl.py
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@ -1211,7 +1211,7 @@ def test_subclass(self):
ctx = ssl.SSLContext(ssl.PROTOCOL_TLSv1)
with socket.socket() as s:
s.bind(("127.0.0.1", 0))
s.listen(5)
s.listen()
c = socket.socket()
c.connect(s.getsockname())
c.setblocking(False)
@ -1736,7 +1736,7 @@ def start(self, flag=None):
def run(self):
self.sock.settimeout(0.05)
self.sock.listen(5)
self.sock.listen()
self.active = True
if self.flag:
# signal an event
@ -2162,7 +2162,7 @@ def test_rude_shutdown(self):
# and sets Event `listener_gone` to let the main thread know
# the socket is gone.
def listener():
s.listen(5)
s.listen()
listener_ready.set()
newsock, addr = s.accept()
newsock.close()
@ -2590,7 +2590,7 @@ def test_handshake_timeout(self):
finish = False
def serve():
server.listen(5)
server.listen()
started.set()
conns = []
while not finish:
@ -2647,7 +2647,7 @@ def test_server_accept(self):
peer = None
def serve():
nonlocal remote, peer
server.listen(5)
server.listen()
# Block on the accept and wait on the connection to close.
evt.set()
remote, peer = server.accept()