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	Rewrote 'newer_pairwise(): more natural (and incompatible) interface,
simpler implementation.
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					 1 changed files with 13 additions and 12 deletions
				
			
		|  | @ -100,22 +100,23 @@ def newer (source, target): | |||
| 
 | ||||
| 
 | ||||
| def newer_pairwise (sources, targets): | ||||
|     """Walk two filename lists in parallel, testing if each 'target' is | ||||
|        up-to-date relative to its corresponding 'source'.  If so, both | ||||
|        are deleted from their respective lists.  Return a list of tuples | ||||
|        containing the deleted (source,target) pairs.""" | ||||
|     """Walk two filename lists in parallel, testing if each source is newer | ||||
|        than its corresponding target.  Return a pair of lists (sources, | ||||
|        targets) where source is newer than target, according to the | ||||
|        semantics of 'newer()'.""" | ||||
| 
 | ||||
|     if len (sources) != len (targets): | ||||
|         raise ValueError, "'sources' and 'targets' must be same length" | ||||
| 
 | ||||
|     goners = [] | ||||
|     for i in range (len (sources)-1, -1, -1): | ||||
|         if not newer (sources[i], targets[i]): | ||||
|             goners.append ((sources[i], targets[i])) | ||||
|             del sources[i] | ||||
|             del targets[i] | ||||
|     goners.reverse() | ||||
|     return goners | ||||
|     # build a pair of lists (sources, targets) where  source is newer | ||||
|     n_sources = [] | ||||
|     n_targets = [] | ||||
|     for i in range (len (sources)): | ||||
|         if newer (sources[i], targets[i]): | ||||
|             n_sources.append (sources[i]) | ||||
|             n_targets.append (targets[i]) | ||||
| 
 | ||||
|     return (n_sources, n_targets) | ||||
| 
 | ||||
| # newer_pairwise () | ||||
| 
 | ||||
|  |  | |||
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	 Greg Ward
						Greg Ward