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Issue #16761: Raise TypeError when int() called with base argument only.

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This commit is contained in:
Serhiy Storchaka 2012-12-28 10:09:54 +02:00
commit c819b077bb
3 changed files with 14 additions and 13 deletions
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12
Lib/test/test_int.py
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@ -233,16 +233,8 @@ def test_keyword_args(self):
self.assertEqual(int(x=1.2), 1)
self.assertEqual(int('100', base=2), 4)
self.assertEqual(int(x='100', base=2), 4)
# For example, PyPy 1.9.0 raised TypeError for these cases because it
# expects x to be a string if base is given.
@support.cpython_only
def test_base_arg_with_no_x_arg(self):
self.assertEqual(int(base=6), 0)
# Even invalid bases don't raise an exception.
self.assertEqual(int(base=1), 0)
self.assertEqual(int(base=1000), 0)
self.assertEqual(int(base='foo'), 0)
self.assertRaises(TypeError, int, base=10)
self.assertRaises(TypeError, int, base=0)
def test_int_base_limits(self):
"""Testing the supported limits of the int() base parameter."""