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needforspeed: speed up unicode repeat, unicode string copy

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This commit is contained in:
Fredrik Lundh 2006-05-22 16:29:30 +00:00
parent d82c3105cc
commit f1d60a5384
2 changed files with 14 additions and 8 deletions
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11
Include/unicodeobject.h
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@ -352,12 +352,15 @@ typedef PY_UNICODE_TYPE Py_UNICODE;
Py_UNICODE_ISDIGIT(ch) || \
Py_UNICODE_ISNUMERIC(ch))
#define Py_UNICODE_COPY(target, source, length)\
(memcpy((target), (source), (length)*sizeof(Py_UNICODE)))
#define Py_UNICODE_COPY(target, source, length) do\
{int i; Py_UNICODE *t = (target); const Py_UNICODE *s = (source);\
for (i = 0; i < (length); i++) t[i] = s[i];\
} while (0)
#define Py_UNICODE_FILL(target, value, length) do\
{int i; for (i = 0; i < (length); i++) (target)[i] = (value);}\
while (0)
{int i; Py_UNICODE *t = (target); Py_UNICODE v = (value);\
for (i = 0; i < (length); i++) t[i] = v;\
} while (0)
#define Py_UNICODE_MATCH(string, offset, substring)\
((*((string)->str + (offset)) == *((substring)->str)) &&\

11
Objects/unicodeobject.c
View file

@ -5898,10 +5898,13 @@ unicode_repeat(PyUnicodeObject *str, Py_ssize_t len)
p = u->str;
while (len-- > 0) {
Py_UNICODE_COPY(p, str->str, str->length);
p += str->length;
}
if (str->length == 1 && len > 0) {
Py_UNICODE_FILL(p, str->str[0], len);
} else
while (len-- > 0) {
Py_UNICODE_COPY(p, str->str, str->length);
p += str->length;
}
return (PyObject*) u;
}