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			118 lines
		
	
	
	
		
			3.3 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
			
		
		
	
	
			118 lines
		
	
	
	
		
			3.3 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
| """Bisection algorithms."""
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| 
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| 
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| def insort_right(a, x, lo=0, hi=None, *, key=None):
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|     """Insert item x in list a, and keep it sorted assuming a is sorted.
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| 
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|     If x is already in a, insert it to the right of the rightmost x.
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| 
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|     Optional args lo (default 0) and hi (default len(a)) bound the
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|     slice of a to be searched.
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| 
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|     A custom key function can be supplied to customize the sort order.
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|     """
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|     if key is None:
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|         lo = bisect_right(a, x, lo, hi)
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|     else:
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|         lo = bisect_right(a, key(x), lo, hi, key=key)
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|     a.insert(lo, x)
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| 
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| 
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| def bisect_right(a, x, lo=0, hi=None, *, key=None):
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|     """Return the index where to insert item x in list a, assuming a is sorted.
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| 
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|     The return value i is such that all e in a[:i] have e <= x, and all e in
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|     a[i:] have e > x.  So if x already appears in the list, a.insert(i, x) will
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|     insert just after the rightmost x already there.
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| 
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|     Optional args lo (default 0) and hi (default len(a)) bound the
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|     slice of a to be searched.
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| 
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|     A custom key function can be supplied to customize the sort order.
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|     """
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| 
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|     if lo < 0:
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|         raise ValueError('lo must be non-negative')
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|     if hi is None:
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|         hi = len(a)
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|     # Note, the comparison uses "<" to match the
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|     # __lt__() logic in list.sort() and in heapq.
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|     if key is None:
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|         while lo < hi:
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|             mid = (lo + hi) // 2
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|             if x < a[mid]:
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|                 hi = mid
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|             else:
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|                 lo = mid + 1
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|     else:
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|         while lo < hi:
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|             mid = (lo + hi) // 2
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|             if x < key(a[mid]):
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|                 hi = mid
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|             else:
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|                 lo = mid + 1
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|     return lo
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| 
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| 
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| def insort_left(a, x, lo=0, hi=None, *, key=None):
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|     """Insert item x in list a, and keep it sorted assuming a is sorted.
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| 
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|     If x is already in a, insert it to the left of the leftmost x.
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| 
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|     Optional args lo (default 0) and hi (default len(a)) bound the
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|     slice of a to be searched.
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| 
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|     A custom key function can be supplied to customize the sort order.
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|     """
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| 
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|     if key is None:
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|         lo = bisect_left(a, x, lo, hi)
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|     else:
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|         lo = bisect_left(a, key(x), lo, hi, key=key)
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|     a.insert(lo, x)
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| 
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| def bisect_left(a, x, lo=0, hi=None, *, key=None):
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|     """Return the index where to insert item x in list a, assuming a is sorted.
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| 
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|     The return value i is such that all e in a[:i] have e < x, and all e in
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|     a[i:] have e >= x.  So if x already appears in the list, a.insert(i, x) will
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|     insert just before the leftmost x already there.
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| 
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|     Optional args lo (default 0) and hi (default len(a)) bound the
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|     slice of a to be searched.
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| 
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|     A custom key function can be supplied to customize the sort order.
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|     """
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| 
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|     if lo < 0:
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|         raise ValueError('lo must be non-negative')
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|     if hi is None:
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|         hi = len(a)
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|     # Note, the comparison uses "<" to match the
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|     # __lt__() logic in list.sort() and in heapq.
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|     if key is None:
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|         while lo < hi:
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|             mid = (lo + hi) // 2
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|             if a[mid] < x:
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|                 lo = mid + 1
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|             else:
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|                 hi = mid
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|     else:
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|         while lo < hi:
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|             mid = (lo + hi) // 2
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|             if key(a[mid]) < x:
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|                 lo = mid + 1
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|             else:
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|                 hi = mid
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|     return lo
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| 
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| 
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| # Overwrite above definitions with a fast C implementation
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| try:
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|     from _bisect import *
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| except ImportError:
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|     pass
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| 
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| # Create aliases
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| bisect = bisect_right
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| insort = insort_right
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