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954a7427ba
It did not work because the signature of code object constructor was changed. Also, it used old format of bytecode (pre-wordcode).
19 lines
628 B
Python
19 lines
628 B
Python
"""
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Broken bytecode objects can easily crash the interpreter.
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This is not going to be fixed. It is generally agreed that there is no
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point in writing a bytecode verifier and putting it in CPython just for
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this. Moreover, a verifier is bound to accept only a subset of all safe
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bytecodes, so it could lead to unnecessary breakage.
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For security purposes, "restricted" interpreters are not going to let
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the user build or load random bytecodes anyway. Otherwise, this is a
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"won't fix" case.
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"""
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import types
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co = types.CodeType(0, 0, 0, 0, 0, 0, b'\x04\x00\x71\x00',
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(), (), (), '', '', 1, b'')
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exec(co)
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