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aaa83cdfab
* bpo-44771: Apply changes from importlib_resources@3b24bd6307 * Add blurb * Exclude namespacedata01 from eol conversion.
84 lines
2.6 KiB
Python
84 lines
2.6 KiB
Python
import os
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import pathlib
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import types
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from typing import Union, Iterable, ContextManager, BinaryIO, TextIO
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from . import _common
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Package = Union[types.ModuleType, str]
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Resource = Union[str, os.PathLike]
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def open_binary(package: Package, resource: Resource) -> BinaryIO:
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"""Return a file-like object opened for binary reading of the resource."""
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return (_common.files(package) / _common.normalize_path(resource)).open('rb')
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def read_binary(package: Package, resource: Resource) -> bytes:
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"""Return the binary contents of the resource."""
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return (_common.files(package) / _common.normalize_path(resource)).read_bytes()
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def open_text(
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package: Package,
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resource: Resource,
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encoding: str = 'utf-8',
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errors: str = 'strict',
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) -> TextIO:
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"""Return a file-like object opened for text reading of the resource."""
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return (_common.files(package) / _common.normalize_path(resource)).open(
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'r', encoding=encoding, errors=errors
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)
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def read_text(
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package: Package,
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resource: Resource,
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encoding: str = 'utf-8',
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errors: str = 'strict',
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) -> str:
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"""Return the decoded string of the resource.
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The decoding-related arguments have the same semantics as those of
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bytes.decode().
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"""
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with open_text(package, resource, encoding, errors) as fp:
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return fp.read()
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def contents(package: Package) -> Iterable[str]:
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"""Return an iterable of entries in `package`.
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Note that not all entries are resources. Specifically, directories are
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not considered resources. Use `is_resource()` on each entry returned here
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to check if it is a resource or not.
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"""
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return [path.name for path in _common.files(package).iterdir()]
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def is_resource(package: Package, name: str) -> bool:
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"""True if `name` is a resource inside `package`.
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Directories are *not* resources.
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"""
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resource = _common.normalize_path(name)
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return any(
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traversable.name == resource and traversable.is_file()
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for traversable in _common.files(package).iterdir()
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)
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def path(
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package: Package,
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resource: Resource,
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) -> ContextManager[pathlib.Path]:
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"""A context manager providing a file path object to the resource.
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If the resource does not already exist on its own on the file system,
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a temporary file will be created. If the file was created, the file
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will be deleted upon exiting the context manager (no exception is
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raised if the file was deleted prior to the context manager
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exiting).
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"""
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return _common.as_file(_common.files(package) / _common.normalize_path(resource))
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