math: rename Modf parameter int to integer

Avoid using int as a parameter name. Also, rename frac to
fractional for consistency.

Addresses comment on CL 694896:
https://go-review.googlesource.com/c/go/+/694896/comment/a9723a07_8352e3aa/

Change-Id: Icedeecf65ad2f51d4e8d5bcf6e64c0eae9885dec
Reviewed-on: https://go-review.googlesource.com/c/go/+/699035
Auto-Submit: Sean Liao <sean@liao.dev>
Reviewed-by: Cherry Mui <cherryyz@google.com>
Reviewed-by: Michael Pratt <mpratt@google.com>
LUCI-TryBot-Result: Go LUCI <golang-scoped@luci-project-accounts.iam.gserviceaccount.com>
Reviewed-by: Sean Liao <sean@liao.dev>
Reviewed-by: Joel Sing <joel@sing.id.au>
This commit is contained in:
Michael Munday 2025-08-25 22:52:02 +01:00 committed by Gopher Robot
parent 2a7f1d47b0
commit 3e596d448f

View file

@ -11,8 +11,8 @@ package math
//
// Modf(±Inf) = ±Inf, NaN
// Modf(NaN) = NaN, NaN
func Modf(f float64) (int float64, frac float64) {
int = Trunc(f)
frac = Copysign(f-int, f)
func Modf(f float64) (integer float64, fractional float64) {
integer = Trunc(f)
fractional = Copysign(f-integer, f)
return
}