runtime: accept timeout from non-timeout semaphore wait on OS X

Looking at the kernel sources, I don't see how this is possible.
But obviously it is. Just try again.

Fixes #17161.

Change-Id: Iea7d53f7cf75944792d2f75a0d07129831c7bcdb
Reviewed-on: https://go-review.googlesource.com/31823
Run-TryBot: Russ Cox <rsc@golang.org>
TryBot-Result: Gobot Gobot <gobot@golang.org>
Reviewed-by: Ian Lance Taylor <iant@golang.org>
Reviewed-by: Brad Fitzpatrick <bradfitz@golang.org>
This commit is contained in:
Russ Cox 2016-10-24 20:47:31 -04:00
parent b4ce38ec57
commit 71cf409dbd

View file

@ -414,7 +414,10 @@ func semasleep1(ns int64) int32 {
if r == 0 {
break
}
if r == _KERN_ABORTED { // interrupted
// Note: We don't know how this call (with no timeout) can get _KERN_OPERATION_TIMED_OUT,
// but it does reliably, though at a very low rate, on OS X 10.8, 10.9, 10.10, and 10.11.
// See golang.org/issue/17161.
if r == _KERN_ABORTED || r == _KERN_OPERATION_TIMED_OUT { // interrupted
continue
}
macherror(r, "semaphore_wait")