[dev.typeparams] runtime: make deferproc take a func() argument

Previously it takes a *funcval, as it can be any function types.
Now it must be func(). Make it so.

Change-Id: I04273047b024386f55dbbd5fbda4767cbee7ac93
Reviewed-on: https://go-review.googlesource.com/c/go/+/325918
Trust: Cherry Mui <cherryyz@google.com>
Run-TryBot: Cherry Mui <cherryyz@google.com>
TryBot-Result: Go Bot <gobot@golang.org>
Reviewed-by: Michael Knyszek <mknyszek@google.com>
This commit is contained in:
Cherry Mui 2021-06-04 18:30:51 -04:00
parent 8e5304f729
commit 83da32749c
4 changed files with 17 additions and 25 deletions

View file

@ -954,10 +954,10 @@ type _defer struct {
// defers. We have only one defer record for the entire frame (which may
// currently have 0, 1, or more defers active).
openDefer bool
sp uintptr // sp at time of defer
pc uintptr // pc at time of defer
fn *funcval // can be nil for open-coded defers
_panic *_panic // panic that is running defer
sp uintptr // sp at time of defer
pc uintptr // pc at time of defer
fn func() // can be nil for open-coded defers
_panic *_panic // panic that is running defer
link *_defer
// If openDefer is true, the fields below record values about the stack