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								/*
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								 * Copyright (c) 2020, Stephan Unverwerth <s.unverwerth@serenityos.org>
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								 * Copyright (c) 2021-2022, David Tuin <davidot@serenityos.org>
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								 *
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								 * SPDX-License-Identifier: BSD-2-Clause
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								 */
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								#include <AK/StringView.h>
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								#include <AK/Vector.h>
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								#include <LibJS/ParserError.h>
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								#include <LibJS/Token.h>
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								namespace JS {
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											2023-02-16 11:03:49 -05:00
										 
									 
								 
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								ErrorOr<String> ParserError::to_string() const
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								{
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								    if (!position.has_value())
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								        return String::from_deprecated_string(message);
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								    return String::formatted("{} (line: {}, column: {})", message, position.value().line, position.value().column);
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								}
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											2022-12-06 01:12:49 +00:00
										 
									 
								 
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								DeprecatedString ParserError::to_deprecated_string() const
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								{
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								    if (!position.has_value())
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								        return message;
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											2022-12-04 18:02:33 +00:00
										 
									 
								 
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								    return DeprecatedString::formatted("{} (line: {}, column: {})", message, position.value().line, position.value().column);
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								}
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											2022-12-04 18:02:33 +00:00
										 
									 
								 
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								DeprecatedString ParserError::source_location_hint(StringView source, char const spacer, char const indicator) const
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								{
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								    if (!position.has_value())
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								        return {};
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								    // We need to modify the source to match what the lexer considers one line - normalizing
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								    // line terminators to \n is easier than splitting using all different LT characters.
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								    DeprecatedString source_string = source.replace("\r\n"sv, "\n"sv, ReplaceMode::All).replace("\r"sv, "\n"sv, ReplaceMode::All).replace(LINE_SEPARATOR_STRING, "\n"sv, ReplaceMode::All).replace(PARAGRAPH_SEPARATOR_STRING, "\n"sv, ReplaceMode::All);
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								    StringBuilder builder;
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								    builder.append(source_string.split_view('\n', SplitBehavior::KeepEmpty)[position.value().line - 1]);
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								    builder.append('\n');
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								    for (size_t i = 0; i < position.value().column - 1; ++i)
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								        builder.append(spacer);
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								    builder.append(indicator);
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											2023-01-26 18:58:09 +00:00
										 
									 
								 
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								    return builder.to_deprecated_string();
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								}
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								}
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