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babfd70ca7
This ensures that we are explicitly declaring the allocator to use when allocating a cell(-inheriting) type, instead of silently falling back to size-based allocation. Since this is done in allocate_cell, this will only be detected for types that are actively being allocated. However, since that means they're _not_ being allocated, that means it's safe to not declare an allocator to use for those. For example, the base TypedArray<T>, which is never directly allocated and only the defined specializations are ever allocated.
54 lines
1.2 KiB
C++
54 lines
1.2 KiB
C++
/*
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* Copyright (c) 2023, Andreas Kling <andreas@ladybird.org>
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*
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* SPDX-License-Identifier: BSD-2-Clause
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*/
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#pragma once
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#include <AK/Function.h>
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#include <LibGC/Cell.h>
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#include <LibGC/Heap.h>
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namespace GC {
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template<typename T>
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class Function final : public Cell {
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GC_CELL(Function, Cell);
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GC_DECLARE_ALLOCATOR(Function);
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public:
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static Ref<Function> create(Heap& heap, ESCAPING AK::Function<T> function)
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{
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return heap.allocate<Function>(move(function));
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}
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virtual ~Function() override = default;
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[[nodiscard]] AK::Function<T> const& function() const { return m_function; }
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private:
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Function(AK::Function<T> function)
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: m_function(move(function))
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{
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}
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virtual void visit_edges(Visitor& visitor) override
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{
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Base::visit_edges(visitor);
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visitor.visit_possible_values(m_function.raw_capture_range());
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}
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AK::Function<T> m_function;
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};
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template<typename Callable, typename T = EquivalentFunctionType<Callable>>
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static Ref<Function<T>> create_function(Heap& heap, ESCAPING Callable&& function)
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{
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return Function<T>::create(heap, AK::Function<T> { forward<Callable>(function) });
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}
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template<typename T>
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GC_DEFINE_ALLOCATOR(Function<T>);
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}
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