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babfd70ca7
This ensures that we are explicitly declaring the allocator to use when allocating a cell(-inheriting) type, instead of silently falling back to size-based allocation. Since this is done in allocate_cell, this will only be detected for types that are actively being allocated. However, since that means they're _not_ being allocated, that means it's safe to not declare an allocator to use for those. For example, the base TypedArray<T>, which is never directly allocated and only the defined specializations are ever allocated.
38 lines
714 B
C++
38 lines
714 B
C++
/*
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* Copyright (c) 2025, Andreas Kling <andreas@ladybird.org>
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*
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* SPDX-License-Identifier: BSD-2-Clause
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*/
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#include <LibGC/Cell.h>
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#pragma once
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namespace GC {
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template<typename T>
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class HeapVector : public Cell {
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GC_CELL(HeapVector, Cell);
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GC_DECLARE_ALLOCATOR(HeapVector);
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public:
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HeapVector() = default;
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virtual ~HeapVector() override = default;
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auto& elements() { return m_elements; }
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auto const& elements() const { return m_elements; }
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virtual void visit_edges(Visitor& visitor) override
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{
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Base::visit_edges(visitor);
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visitor.visit(m_elements);
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}
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private:
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Vector<T> m_elements;
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};
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template<typename T>
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GC_DEFINE_ALLOCATOR(HeapVector<T>);
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}
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